What is the base: acid ratio at pH 7 for acid of pK6?
a. 0.01
b. 0.1
c. 1.0
d. 10
e. 100
(d) According to Henderson Hasselbalch's equation, pH = pK + Log base/acid. By compensation, Log (base / acid)= 1, thus base: acid = 10:1.1
a. 0.01
b. 0.1
c. 1.0
d. 10
e. 100
(d) According to Henderson Hasselbalch's equation, pH = pK + Log base/acid. By compensation, Log (base / acid)= 1, thus base: acid = 10:1.1